This problem is extracted from HackerRank: Counting Valleys. Its rating is Easy. We will be using Python 3 to solve this problem. Do try to solve it yourself first in HackerRank before peeking at the solution. ğŸ™‚

### The Problem

Gary is an avid hiker. He tracks his hikes meticulously, paying close attention to small details like topography. During his last hike, he took exactly

`n`

steps. For every step he took, he noted if it was an uphill or a downhill step. Gary’s hikes start and end at sea level. We define the following terms:

- A mountain is a non-empty sequence of consecutive steps above sea level, starting with a step up from sea level and ending with a step down to sea level.
- A valley is a non-empty sequence of consecutive steps below sea level, starting with a step down from sea level and ending with a step up to sea level.
Given Gary’s sequence of up and down steps during his last hike, find and print the number of valleys he walked through.

Input Format

The first line contains an integer,`n`

, denoting the number of steps in Gary’s hike.The second line contains a single string of

`n`

characters. Each character is`∈ {U, D}`

(where U indicates a step up and D indicates a step down), and the`i`

character in the string describes Gary’s^{th}`i`

step during the hike.^{th}

Constraints

`2 ≤ N ≤ 10`

^{6}

Output Format

Print a single integer denoting the number of valleys Gary walked through during his hike.

Sample Input

`8`

UDDDUDUU

Sample Output

`1`

Explanation

If we represent`_`

as sea level, a step up as`/`

, and a step down as`\`

, Gary’s hike can be drawn as:

It’s clear that there is only one valley there, so we print 1 on a new line.

### Approaching the Problem

`count_valleys`

that will take in two arguments, `n`

and `steps`

, where `n`

is the total number of steps Gary takes, and `steps`

is a string object containing a string of `U`

or `D`

characters. This function will return the number of valleys.
First, think about what you need to keep track of. The most essential bit is, of course, the number of valleys, as we have to return this value.

Using the illustration in the Explanation portion in the question, we have to know the overall topography by using our program to know Gary’s position every step he takes. We can use an integer variable, `level`

, to track how far above or below the sea level Gary is. This variable `level`

will start at 0 to indicate Gary’s starting position at sea level. Whenever we encounter `'U'`

in Gary’s step, we will increase `level`

by 1. When we encounter `'D'`

, we will decrease `level`

by 1. This means that when the value of level is `positive`

, he is above sea level on a mountain, and when it is negative, he is in a valley.

def count_valleys(n, steps): num_valleys = 0 # number of valleys level = 0 # starts at sea level for d in steps: if d == 'U': # going upslope level += 1 else: # going downslope level -= 1 return num_valleys

At this point, we are keeping track of Gary’s position relative to sea level, but not the number of valleys yet. Next, we should think about when we can increment `num_valleys`

.

Let’s break down the problem into more digestible parts:

- At each loop, we analyse the direction Gary does: It can only be
`'U'`

(upslope) or`'D'`

(downslope). - When it’s a
`'U'`

, there’s no reason for us to increment`num_valleys`

, since Gary is climbing back up. - Now, when it’s a
`'D'`

, how can we consider it a*new valley*, so that we may increment`num_valleys`

?

To answer the last point, for it to be considered a *new valley*, the `level`

variable must be 0 in the previous loop (in other words, he must be at sea level before stepping downslope). This special consideration must be included in the `else`

case of our function above (where `d == 'D'`

).

Hence, before we decrement `level`

, we need to do a test if Gary was previously at sea level (`level == 0`

). If so, then increment `num_valleys`

.

Final version of our function:

def count_valleys(n, steps): num_valleys = 0 # number of valleys level = 0 # starts at sea level for d in steps: if d == 'U': # going upslope level += 1 else: # going downslope if level == 0: num_valleys += 1 level -= 1 return num_valleys

### Final Solution

def count_valleys(n, steps): num_valleys = 0 # number of valleys level = 0 # starts at sea level for d in steps: if d == 'U': # going upslope level += 1 else: # going downslope if level == 0: num_valleys += 1 level -= 1 return num_valleys n = int(input().strip()) steps = input().strip() result = count_valleys(n, steps) print(result)